Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
bartleby

Concept explainers

Question
Book Icon
Chapter 7.SE, Problem 53AP
Interpretation Introduction

Interpretation:

To assign E or Z configuration to the double bonds in Tamoxifen and Clomiphene.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom of the two substituents separately. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms away from double bond are considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms. The isomer that has the higher ranked groups on each carbon are on the same side of the double bond is said to have Z configuration. If the higher ranked groups are on opposite sides, the alkene is said to have E configuration.

To assign:

The configuration for the double bonds in Tamoxifen and Clomiphene as E or Z.

Blurred answer
Students have asked these similar questions
Two useful organic compounds that contain Cl atoms are vinyl chloride (CH2 = CHCI) and chloroethane (CH;CH;CI). Vinyl chloride is the starting material used to prepare poly (vinyl chloride), a plastic used in insulation, pipes, and bottles. Chloroethane (ethyl chloride) is a local anesthetic. Why is the C- Cl bond of vinyl chloride stronger than the C– CIl bond in chloroethane.
A single bond between two carbons with different hybridizations has a small dipole. What is the direction of the dipole in the indicated bonds?
Compare the structures of 1,4-pentadiene and divinylamine: 1,4-Pentadiene The first compound does not absorb UV light in the region between 200 and 400 nm. The second compound does absorb light above 200 nm. Using this information, identify the hybridization state of the nitrogen atom in divinylamine. O sp³ hybridized O sp³d hybridized sp² hybridized O sp hybridized N H Divinylamine Justify your answer. The lone pair is a part of the TT system in the second compound. Therefore the compound is conjugated ✓ .As such, the compound absorbs light above 200 nm (UV light). In contrast, 1,4-pentadiene has two double bonds and therefore does not absorb UV light in the region between 200 and 400 nm. 3 isolated cumulated conjugated

Chapter 7 Solutions

Organic Chemistry

Ch. 7.5 - Which member in each of the following sets ranks...Ch. 7.5 - Prob. 12PCh. 7.5 - Prob. 13PCh. 7.5 - Prob. 14PCh. 7.6 - Prob. 15PCh. 7.8 - Prob. 16PCh. 7.8 - Prob. 17PCh. 7.9 - Show the structures of the carbocation...Ch. 7.9 - Draw a skeletal structure of the following...Ch. 7.10 - Prob. 20PCh. 7.11 - On treatment with HBr, vinylcyclohexane undergoes...Ch. 7.SE - Prob. 22VCCh. 7.SE - Prob. 23VCCh. 7.SE - The following carbocation is an intermediate in...Ch. 7.SE - Prob. 25VCCh. 7.SE - Predict the major product and show the complete...Ch. 7.SE - Prob. 27MPCh. 7.SE - When 1, 3-butadiene reacts with one mole of HBr,...Ch. 7.SE - When methyl vinyl ether reacts with a strong acid,...Ch. 7.SE - Addition of HCl to 1-isopropylcyclohexene yields a...Ch. 7.SE - Addition of HCl to...Ch. 7.SE - Limonene, a fragrant hydrocarbon found in lemons...Ch. 7.SE - Prob. 33MPCh. 7.SE - Calculate the degree of unsaturation in the...Ch. 7.SE - Prob. 35APCh. 7.SE - Prob. 36APCh. 7.SE - Name the following alkenes:Ch. 7.SE - Draw structures corresponding to the following...Ch. 7.SE - Prob. 39APCh. 7.SE - Prob. 40APCh. 7.SE - Prob. 41APCh. 7.SE - Prob. 42APCh. 7.SE - Prob. 43APCh. 7.SE - Draw and name the 17 alkene isomers, C6H12,...Ch. 7.SE - Prob. 45APCh. 7.SE - Prob. 46APCh. 7.SE - Which of the following E, Z designations are...Ch. 7.SE - Prob. 48APCh. 7.SE - trans-2-Butene is more stable than cis-2-butene by...Ch. 7.SE - Prob. 50APCh. 7.SE - Normally, a trans alkene is more stable than its...Ch. 7.SE - trans-Cyclooctene is less stable than...Ch. 7.SE - Prob. 53APCh. 7.SE - Prob. 54APCh. 7.SE - Use Hammond’s Postulate to determine which...Ch. 7.SE - Prob. 56APCh. 7.SE - Predict the major product in each of the following...Ch. 7.SE - Prob. 58APCh. 7.SE - Prob. 59APCh. 7.SE - Prob. 60APCh. 7.SE - Allene (1,2-propadiene), H2C=C=CH2, has two...Ch. 7.SE - The heat of hydrogenation for allene (Problem...Ch. 7.SE - Retin A, or retinoic acid, is a medication...Ch. 7.SE - Prob. 64APCh. 7.SE - tert-Butyl esters [RC02C(CH3)3] are converted into...Ch. 7.SE - Vinylcyclopropane reacts with HBr to yield a...Ch. 7.SE - Prob. 67APCh. 7.SE - Prob. 68APCh. 7.SE - Prob. 69APCh. 7.SE - Prob. 70APCh. 7.SE - Prob. 71APCh. 7.SE - Reaction of 2, 3-dimethyl-l-butene with HBr leads...
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Living by Chemistry
Chemistry
ISBN:9781464142314
Author:Angelica M. Stacy
Publisher:W. H. Freeman